JavaScript

Calculating the Area of a Shaped Region Using JavaScript’s Integral Method2 min read

When it comes to determining the area of a specific shape, the integral method is a powerful tool. In this web article, we’ll explore a JavaScript example that demonstrates how to leverage this method for area calculation.

JavaScript Code:




Explanation of the Code:

  1. HTML Structure:
    • <!DOCTYPE html> declares the document type and version.
    • The <html> element wraps the entire HTML content.
    • The <head> section contains metadata, including character set and the page title.
    • The <body> section holds the main content of the page.
  2. JavaScript Code:
    • The Math.integral function is defined to calculate the integral of a quadratic equation ax^2 + bx + c over a given range.
    • Parameters:
      • a, b, and c are coefficients of the quadratic equation.
      • xa and xb define the integral limits.
      • h determines the number of iterations, influencing the accuracy of the result.
    • Inside the function, a loop iterates through the specified range, calculating the value of the quadratic equation at each point and accumulating the area using the integral method.
  3. Sample Usage:
    • The script then uses the defined Math.integral function with a sample input (1, 4, 2, 10, 50, 100).
    • The result is displayed using window.alert.

This example provides a basic understanding of how to implement the integral method in JavaScript for area calculations, specifically for quadratic equations. Adjust the coefficients and range according to your specific requirements.

1 Comment

  • a very specific integral. might be better to accept them as an array indicating the order, so:
    [1,2,3,4,5]=5x^4+4x^3+3x^2+2x+1, then you would build it as:
    function integral(input,x)
    {
    var res=0;
    for(var i=0;i<input.length;i++)
    {
    power=i+1;
    res+=((input[i]*Math.pow(x,power))/power);
    }
    return res;
    }

    if one of the numbers was subtracted put in a negative so 2x^2-3x+1 would be [1,-3,2]

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